Given three integers A, B and C in [−263, 263], you are supposed to tell whether A+B>C.

## Input Specification:

The first line of the input gives the positive number of test cases, T (≤10). Then T test cases follow, each consists of a single line containing three integers A, B and C, separated by single spaces.

## Output Specification:

For each test case, output in one line Case #X: true if A+B>C, or Case #X: false otherwise, where X is the case number (starting from 1).

## Sample Input:

3
1 2 3
2 3 4
9223372036854775807 -9223372036854775808 0

Case #1: false
Case #2: true
Case #3: false

## 解答

1. 负数+负数，A+B为正数或0时溢出（当A，B都是char类型时，-128+(-128)=0,long long类型也类似）
2. 正数+正数，A+B为负数时溢出，A+B不会等于0
#include<iostream>
using namespace std;
int main()
{
int n;
long long a, b, c;
bool cmp;
scanf("%d", &n);
for (int i = 0; i < n; i++) {
scanf("%lld %lld %lld", &a, &b, &c);
long long tmp = a + b;
if (a > 0 && b > 0 && tmp < 0) cmp = true;
else if (a < 0 && b < 0 && tmp >= 0) cmp = false;
else if (tmp > c) cmp = true;
else cmp = false;
if (cmp) printf("Case #%d: true\n", i + 1);
else printf("Case #%d: false\n", i + 1);
}
return 0;
}